AISCAISC 360-22
Chapter F Design of members for flexure

F2Doubly symmetric compact I-shaped members and channels bent about their major axis

PDF page 121 · AISC 360-22

This section applies to doubly symmetric I-shaped members and channels bent about their major axis, having compact webs and compact flanges as defined in Section B4.1 for flexure.

User Note: For Fy=50ksi(345MPa)F_{y}=50 \mathrm{ksi}(345 \mathrm{MPa}), all current ASTM A6/A6M W, S, M, C, and MC shapes except W21×48,W14×99,W14×90,W12×65,W10×12\mathrm{W} 21 \times 48, \mathrm{W} 14 \times 99, \mathrm{W} 14 \times 90, \mathrm{W} 12 \times 65, \mathrm{W} 10 \times 12, W8×31,W8×10,W6×15,W6×9,W6×8.5\mathrm{W} 8 \times 31, \mathrm{W} 8 \times 10, \mathrm{W} 6 \times 15, \mathrm{W} 6 \times 9, \mathrm{W} 6 \times 8.5, and M4×6\mathrm{M} 4 \times 6 have compact flanges. For Fy70ksi(485MPa)F_{y} \leq 70 \mathrm{ksi}(485 \mathrm{MPa}), all current ASTM A6/A6M W, S, M, HP, C, and MC shapes have compact webs.

The nominal flexural strength, MnM_{n}, shall be the lower value obtained according to the limit states of yielding (plastic moment) and lateral-torsional buckling.

F2.1 Yielding

Mn = Mp = Fy Zx (F2-1)

where

Fy=F_{y}= specified minimum yield stress of the type of steel being used, ksi (MPa)

Zx=plastic\mathrm{Z}_{x}=\mathrm{plastic} section modulus about the xx-axis, in. 3( mm3){ }^{3}\left(\mathrm{~mm}^{3}\right)

F2.2 Lateral-Torsional Buckling

  • (a) When LbLpL_{b} \leq L_{p}, the limit state of lateral-torsional buckling does not apply.
  • (b) When Lp<LbLrL_{p}<L_{b} \leq L_{r}
Mn=CbMp(Mp0.7FySx)(LbLpLrLp)MpM_{n}=C_{b}\left|M_{p}-\left(M_{p}-0.7 F_{y} S_{x}\right)\left(\frac{L_{b}-L_{p}}{L_{r}-L_{p}}\right)\right| \leq M_{p}

(c) When Lb>LrL_{b}>L_{r}

Mn=FcrSxMpM_{n}=F_{c r} S_{x} \leq M_{p}

(F2-3)

where

  • Lb=L_{b}= length between points that are either braced against lateral displacement of the compression flange or braced against twist of the cross section, in. (mm)

Fcr= critical stress, ksi (MPa) F_{c r}=\text { critical stress, ksi (MPa) }

(Lbris)21+0.078JcSxho(Lbris)2\left(\frac{L_{b}}{r_{i s}}\right)^{2} \sqrt{1+0.078 \frac{J c}{S_{x} h_{o}}\left(\frac{L_{b}}{r_{i s}}\right)^{2}}

(F2-4)

E=E \quad= modulus of elasticity of steel

= 29,000 ksi (200 000 MPa)

J=J \quad= torsional constant, in. 4( mm4){ }^{4}\left(\mathrm{~mm}^{4}\right)

SxS_{x} = elastic section modulus taken about the x-axis, in. 3{ }^{3} (mm 3{ }^{3} )

  • ho=h_{o}= distance between the flange centroids, in. (mm)

User Note: The square root term in Equation F2-4 may be conservatively taken as equal to 1.0.

User Note: Equations F2-3 and F2-4 provide identical solutions to the following expression for lateral-torsional buckling of doubly symmetric members that has been presented in past editions of this Specification:

Mcr=CbπLbEIyGJ+(πELb)2IyCwM_{c r}=C_{b} \frac{\pi}{L_{b}} \sqrt{E I_{y} G J+\left(\frac{\pi E}{L_{b}}\right)^{2} I_{y} C_{w}}

The advantage of Equations F2-3 and F2-4 is that the form is very similar to the expression for lateral-torsional buckling of singly symmetric I-shaped members given in Equations F4-3 and F4-5.

Lp, the limiting laterally unbraced length for the limit state of yielding, in. (mm), is

Lp=1.76ryEFyL_{p}=1.76 r_{y} \sqrt{\frac{E}{F_{y}}}

(F2-5)

LrL_{r}, the limiting unbraced length for the limit state of inelastic lateral-torsional buckling, in. (mm), is

Lr=1.95rtsE0.7FyJcSxho+(JcSxho)2+6.76(0.7FyE)2L_{r}=1.95 r_{t s} \frac{E}{0.7 F_{y}} \sqrt{\frac{J c}{S_{x} h_{o}}}+\sqrt{\left(\frac{J c}{S_{x} h_{o}}\right)^{2}+6.76\left(\frac{0.7 F_{y}}{E}\right)^{2}}

where

ry= radius of gyration about y-axis, in. (mm) rts2=IyCwSx\begin{aligned} r_{y} & =\text { radius of gyration about } y \text {-axis, in. (mm) } \\ r_{t s}^{2} & =\frac{\sqrt{I_{y} C_{w}}}{S_{x}}\end{aligned} (F2-7)

and the coefficient cc is determined as follows:

(1) For doubly symmetric I-shapes

c=1c=1

(F2-8a)

(2) For channels

c=ho2IyCwc=\frac{h_{o}}{2} \sqrt{\frac{I_{y}}{C_{w}}}

(F2-8b)

where

Iy=I_{y}= moment of inertia about the y-axis, in. 4( mm4){ }^{4}\left(\mathrm{~mm}^{4}\right)

User Note: For doubly symmetric I-shapes with rectangular flanges, Cw=Iyho24C_{w}=\frac{I_{y} h_{o}^{2}}{4}, and, thus, Equation F2-7 becomes

Ish r 25

rtsr_{t s} may be approximated accurately to conservatively as the radius of gyration of the compression flange plus one-sixth of the web:

ris=bf12(1+16htwbftf)r_{i s}=\frac{b_{f}}{\sqrt{12\left(1+\frac{1}{6} \frac{h t_{w}}{b_{f} t_{f}}\right)}}

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