AISCAISC 360-22
Chapter E Design of members for compression

E4Torsional and flexural-torsional buckling of single angles and members without slender elements

PDF page 109 · AISC 360-22

This section applies to singly symmetric and unsymmetric members, certain doubly symmetric members, such as cruciform or built-up members, and doubly symmetric members when the torsional unbraced length exceeds the lateral unbraced length, all without slender elements. These provisions also apply to single angles with b/t>0.71E/Fyb / t>0.71 \sqrt{E / F_{y}}, where bb is the width of the longest leg and tt is the thickness.

The nominal compressive strength, PnP_{n}, shall be determined based on the limit states of torsional and flexural-torsional buckling:

Pn=FnAgP_{n}=F_{n} A_{g}

(E4-1)

The nominal stress, FnF_{n}, shall be determined according to Equation E3-2 or E3-3, using the torsional or flexural-torsional elastic buckling stress, FeF_{e}, determined as follows:

  • (a) For doubly symmetric members twisting about the shear center
Fe=(π2ECwLcz2+GJ)1Ix+IyF_{e}=\left(\frac{\pi^{2} E C_{w}}{L_{c z}^{2}}+G J\right) \frac{1}{I_{x}+I_{y}}

(E4-2)

  • (b) For singly symmetric members twisting about the shear center where y is the axis of symmetry
Fe=(Fey+Fez2H)[114FeyFezH(Fey+Fez)2]F_{e}=\left(\frac{F_{e y}+F_{e z}}{2 H}\right)\left[1-\sqrt{1-\frac{4 F_{e y} F_{e z} H}{\left(F_{e y}+F_{e z}\right)^{2}}}\right]

(E4-3)

User Note: For singly symmetric members with the xx-axis as the axis of symmetry, such as channels, Equation E4-3 is applicable with FeyF_{e y} replaced by FexF_{e x}.

(c) For unsymmetric members twisting about the shear center, FeF_{e} is the lowest root of the cubic equation

(FeFex)(FeFey)(FeFez)Fe2(FeFey)(xoro)2Fe2(FeFex)(yoro)2=0\left(F_{e}-F_{e x}\right)\left(F_{e}-F_{e y}\right)\left(F_{e}-F_{e z}\right)-F_{e}^{2}\left(F_{e}-F_{e y}\right)\left(\frac{x_{o}}{r_{o}}\right)^{2}-F_{e}^{2}\left(F_{e}-F_{e x}\right)\left(\frac{y_{o}}{r_{o}}\right)^{2}=0

(E4-4)

where

Cw= warping constant, in. 6( mm6)Fex=π2E(Lcxrx)2\begin{aligned} C_{w} & =\text { warping constant, in. }^{6}\left(\mathrm{~mm}^{6}\right) \\ F_{e x} & =\frac{\pi^{2} E}{\left(\frac{L_{c x}}{r_{x}}\right)^{2}} \end{aligned}

(E4-5)

Equation

Figure description:

  • Equation (E4-6: Fey=π2E(Lcyry)2F_{ey} = \frac{\pi^2 E}{\left(\frac{L_{cy}}{r_y}\right)^2}
  • Key Entities:
    • FeyF_{ey}: Elastic buckling stress about the y-axis.
    • EE: Modulus of elasticity of steel.
    • LcyL_{cy}: Effective length of the member for buckling about the y-axis.
    • ryr_y: Radius of gyration about the y-axis.
Fez=(π2ECwLcz2+GJ)1Agrˉo2G= shear modulus of elasticity of steel =11,200ksi(77,200MPa)H= flexural constant =1xo2+yo2r2\begin{aligned} F_{e z} & =\left(\frac{\pi^{2} E C_{w}}{L_{c z}^{2}}+G J\right) \frac{1}{A_{g} \bar{r}_{o}^{2}} \\ G & =\text { shear modulus of elasticity of steel } \\ & =11,200 \mathrm{ksi}(77,200 \mathrm{MPa}) \\ H & =\text { flexural constant } \\ & =1-\frac{x_{o}^{2}+y_{o}^{2}}{r^{2}} \end{aligned}

(E4-7) (E4-8)

Ix,Iy= moment of inertia about the principal axes, in. 4( mm4)J= torsional constant, in. 4( mm4)Kx= effective length factor for flexural buckling about x-axis Ky= effective length factor for flexural buckling about y-axis Kz= effective length factor for torsional buckling about the longitudinal  axis \begin{aligned} I_{x}, I_{y} & =\text { moment of inertia about the principal axes, in. }^{4}\left(\mathrm{~mm}^{4}\right) \\ J & =\text { torsional constant, in. }^{4}\left(\mathrm{~mm}^{4}\right) \\ K_{x} & =\text { effective length factor for flexural buckling about } x \text {-axis } \\ K_{y} & =\text { effective length factor for flexural buckling about } y \text {-axis } \\ K_{z} & =\text { effective length factor for torsional buckling about the longitudinal } \\ & \text { axis }\end{aligned}

Lcx= effective length of member for buckling about x-axis, in. (mm) =KxLx\begin{aligned} L_{c x} & =\text { effective length of member for buckling about } x \text {-axis, in. (mm) } \\ & =K_{x} L_{x}\end{aligned}

Lcy= effective length of member for buckling about y-axis, in. (mm) =KyLy\begin{aligned} L_{c y} & =\text { effective length of member for buckling about } y \text {-axis, in. (mm) } \\ & =K_{y} L_{y}\end{aligned}

Lcz= effective length of member for buckling about longitudinal axis,  in. (mm) =KzLz\begin{aligned} L_{c z} & =\text { effective length of member for buckling about longitudinal axis, } \\ & \text { in. (mm) } \\ & =K_{z} L_{z}\end{aligned}

Lx,Ly,Lz= laterally unbraced length of the member for each axis, in. (mm) rˉo= polar radius of gyration about the shear center, in. (mm) rˉo2=xo2+yo2+Ix+IyAgrx= radius of gyration about x-axis, in. (mm) ry= radius of gyration about y-axis, in. (mm) xo,yo= coordinates of the shear center with respect to the centroid, in. (mm) \begin{aligned} L_{x}, L_{y}, L_{z} & =\text { laterally unbraced length of the member for each axis, in. (mm) } \\ \bar{r}_{o} & =\text { polar radius of gyration about the shear center, in. (mm) } \\ \bar{r}_{o}^{2} & =x_{o}^{2}+y_{o}^{2}+\frac{I_{x}+I_{y}}{A_{g}} \\ r_{x} & =\text { radius of gyration about } x \text {-axis, in. (mm) } \\ r_{y} & =\text { radius of gyration about } y \text {-axis, in. (mm) } \\ x_{o}, y_{o} & =\text { coordinates of the shear center with respect to the centroid, in. (mm) }\end{aligned}

User Note: For doubly symmetric I-shaped sections, Cw may be taken as I h y o2 4, where ho is the distance between flange centroids, in lieu of a more precise analysis. For tees and double angles, the term with Cw may be omitted when computing Fez.

  • (d) For doubly symmetric I-shaped members with minor-axis lateral bracing offset from the shear center
Fe=[π2EIyLcz2(ho24+ya2)+GJ]1Agro2F_{e}=\left[\frac{\pi^{2} E I_{y}}{L_{c z}^{2}}\left(\frac{h_{o}^{2}}{4}+y_{a}^{2}\right)+G J\right] \frac{1}{A_{g} r_{o}^{2}}

(E4-10)

where

ho= distance between flange centroids, in. (mm) ro2=rx2+ry2+ya2+xa2xa= bracing offset distance along x-axis =0ya= bracing offset distance along y-axis, in. (mm) \begin{aligned} h_{o} & =\text { distance between flange centroids, in. (mm) } \\ r_{o}^{2} & =r_{x}^{2}+r_{y}^{2}+y_{a}^{2}+x_{a}^{2} \\ x_{a} & =\text { bracing offset distance along } x \text {-axis }=0 \\ y_{a} & =\text { bracing offset distance along } y \text {-axis, in. (mm) } \end{aligned}
  • (e) For doubly symmetric I-shaped members with major-axis lateral bracing offset from the shear center
Fe=π2EIyLcz2(ho24+IxIyxa2)+GJ1Agro2F_{e}=\left|\frac{\pi^{2} E I_{y}}{L_{c z}^{2}}\left(\frac{h_{o}^{2}}{4}+\frac{I_{x}}{I_{y}} x_{a}^{2}\right)+G J\right| \frac{1}{A_{g} r_{o}^{2}}

(E4-12)

where

ro2=rx2+ry2+ya2+xa2xa= bracing offset distance along x-axis, in. (mm) ya= bracing offset distance along y-axis =0\begin{aligned} r_{o}^{2} & =r_{x}^{2}+r_{y}^{2}+y_{a}^{2}+x_{a}^{2} \\ x_{a} & =\text { bracing offset distance along } x \text {-axis, in. (mm) } \\ y_{a} & =\text { bracing offset distance along } y \text {-axis }=0 \end{aligned}
  • (f) For all other members with lateral bracing offset from the shear center, the elastic buckling stress, FeF_{e}, shall be determined by analysis.

User Note: Bracing offset from the shear center is often referred to as constrained-axis torsional buckling and is discussed further in the Commentary. Members that buckle in this mode will exhibit twisting because the braces restrain only lateral movement.