AISCAISC 360-22
Formulas

Formulas: flexural buckling of members without slender elements

PDF page 108 · AISC 360-22

Equation E3-1

The nominal compressive strength, PnP_{n}, shall be determined based on the limit state of flexural buckling:

Pn=FnAgP_{n}=F_{n} A_{g}

Formula 2

(a) When Lcr4.71EFy\frac{L_{c}}{r} \leq 4.71 \sqrt{\frac{E}{F_{y}}} (or FyFe2.25\frac{F_{y}}{F_{e}} \leq 2.25 )

Lcr4.71EFy\frac{L_{c}}{r} \leq 4.71 \sqrt{\frac{E}{F_{y}}}

Formula 3

FyFe2.25\frac{F_{y}}{F_{e}} \leq 2.25

Equation E3-2

Fn=(0.658FyFc)FyF_{n}=\left(0.658 \frac{F_{y}}{F_{c}}\right) F_{y}

Formula 5

(b) When Lcr>4.71EFy\frac{L_{c}}{r}>4.71 \sqrt{\frac{E}{F_{y}}} (or FyFe>2.25\frac{F_{y}}{F_{e}}>2.25 )

Lcr>4.71EFy\frac{L_{c}}{r}>4.71 \sqrt{\frac{E}{F_{y}}}

Formula 6

FyFe>2.25\frac{F_{y}}{F_{e}}>2.25

Equation E3-3

Fn=0.877FeF_{n}=0.877 F_{e}

where

Ag=A_{g}= gross area of member, in. 2( mm2){ }^{2}\left(\mathrm{~mm}^{2}\right)

  • E = modulus of elasticity of steel, ksi (MPa)
  • = 29,000 ksi (200 000 MPa)

Fe=F_{e}= elastic buckling stress determined according to Equation E3-4; or as specified in Appendix 7, Section 7.2.3(b); or through an elastic buckling analysis, as applicable, ksi (MPa)

Found in

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