AISCAISC 360-22
Formulas

Formulas: Local Buckling of Tee Stems and Double-Angle Web Legs in Flexural Compression

PDF page 135 · AISC 360-22

Equation F9-16

Mn=FcrSxM_{n}=F_{c r} S_{x}

where

Sx= elastic section modulus taken about the x-axis, in. 3( mm3)Fcr, the critical stress, is determined as follows: \begin{aligned} S_{x} & =\text { elastic section modulus taken about the } x \text {-axis, in. }^{3}\left(\mathrm{~mm}^{3}\right) \\ F_{c r}, & \text { the critical stress, is determined as follows: }\end{aligned}

Formula 2

(1) When dtw0.84EFy\frac{d}{t_{w}} \leq 0.84 \sqrt{\frac{E}{F_{y}}}

dtw0.84EFy\frac{d}{t_{w}} \leq 0.84 \sqrt{\frac{E}{F_{y}}}

Formula 3

(2) When 0.84EFydtw1.52EFy0.84 \sqrt{\frac{E}{F_{y}}} \leq \frac{d}{t_{w}} \leq 1.52 \sqrt{\frac{E}{F_{y}}}

0.84EFydtw1.52EFy0.84 \sqrt{\frac{E}{F_{y}}} \leq \frac{d}{t_{w}} \leq 1.52 \sqrt{\frac{E}{F_{y}}}

Equation F9-18

Fcr=(1.430.515dtFyE)FyF_{c r}=\left(1.43-0.515 \frac{d}{t} \sqrt{\frac{F_{y}}{E}}\right) F_{y}

Formula 5

(3) When dtw>1.52EFy\frac{d}{t_{w}}>1.52 \sqrt{\frac{E}{F_{y}}}

dtw>1.52EFy\frac{d}{t_{w}}>1.52 \sqrt{\frac{E}{F_{y}}}

Equation F9-19

Fcr=1.52E(dtw)2F_{c r}=\frac{1.52 E}{\left(\frac{d}{t_{w}}\right)^{2}}

Found in

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