AISCAISC 360-22
Formulas

Formulas: Filled Composite Members

PDF page 513 · AISC 360-22

Formula 1

bi=B2twb_i = B - 2t_w (text_label - position: above the cross-section diagram)

bi=B2twb_i = B - 2t_w

Formula 2

Neutral axis location for force equilibrium: ap=2FyHtw+0.85fcbitf4twFy+0.85fcbi\mathbf{a}_{p}=\frac{2 F_{y} H t_{w}+0.85 f_{c}^{\prime} b_{i} t_{f}}{4 t_{w} F_{y}+0.85 f_{c}^{\prime} b_{i}}

ap=2FyHtw+0.85fcbitf4twFy+0.85fcbi\mathbf{a}_{p}=\frac{2 F_{y} H t_{w}+0.85 f_{c}^{\prime} b_{i} t_{f}}{4 t_{w} F_{y}+0.85 f_{c}^{\prime} b_{i}}

Formula 3

| Steel Stress | Stress at y=ayy = a_y | 00 |

y=ayy = a_y

Formula 4

| Steel Stress | Stress at y=2ayy = 2a_y | FyF_y |

y=2ayy = 2a_y

Formula 5

Neutral axis location for force equilibrium: ay=2FyHtw+0.35fcbitf4twFy+0.35fcbi\mathbf{a}_{y}=\frac{2 F_{y} H t_{w}+0.35 f_{c}^{\prime} b_{i} t_{f}}{4 t_{w} F_{y}+0.35 f_{c}^{\prime} b_{i}}

ay=2FyHtw+0.35fcbitf4twFy+0.35fcbi\mathbf{a}_{y}=\frac{2 F_{y} H t_{w}+0.35 f_{c}^{\prime} b_{i} t_{f}}{4 t_{w} F_{y}+0.35 f_{c}^{\prime} b_{i}}

Formula 6

Neutral axis location for force equilibrium: acr=FyHtw+(0.35fc+FyFn)bitftw(Fn+Fy)+0.35fcbi\mathbf{a}_{c r}=\frac{F_{y} H t_{w}+\left(0.35 f_{c}^{\prime}+F_{y}-F_{n}\right) b_{i} t_{f}}{t_{w}\left(F_{n}+F_{y}\right)+0.35 f_{c}^{\prime} b_{i}}

acr=FyHtw+(0.35fc+FyFn)bitftw(Fn+Fy)+0.35fcbi\mathbf{a}_{c r}=\frac{F_{y} H t_{w}+\left(0.35 f_{c}^{\prime}+F_{y}-F_{n}\right) b_{i} t_{f}}{t_{w}\left(F_{n}+F_{y}\right)+0.35 f_{c}^{\prime} b_{i}}

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