Formulas: Shear Strength of Interior Web Panels with $a / h \leq 3$ Considering Tension Field Action

Formula 1

a / h \leq 3

(a) When $h / t_{w} \leq 1.10 \sqrt{k_{y} E / F_{y}}$

h / t_{w} \leq 1.10 \sqrt{k_{y} E / F_{y}}

V_{n}=0.6 F_{y} A_{w}

(b) When $h / t_{w}>1.10 \sqrt{k_{\mathrm{v}} E / F_{\mathrm{y}}}$

h / t_{w}>1.10 \sqrt{k_{\mathrm{v}} E / F_{\mathrm{y}}}

(1) When $2 A_{w} /\left(\left.A_{f c}+A_{f t}\right)\right) \leq 2.5, h / b_{f c} \leq 6.0$ , and $h / b_{f t} \leq 6.0$

2 A_{w} /\left(\left.A_{f c}+A_{f t}\right)\right) \leq 2.5, h / b_{f c} \leq 6.0

h / b_{f t} \leq 6.0

(1) When $2 A_{w} /\left(A_{f c}+A_{f t}\right) \leq 2.5, h / b_{f c} \leq 6.0$ , and $h / b_{f t} \leq 6.0$

2 A_{w} /\left(A_{f c}+A_{f t}\right) \leq 2.5, h / b_{f c} \leq 6.0

V_{n}=0.6 F_{y} A_{w}\left[C_{v 2}+\frac{1-C_{v 2}}{\sqrt{2}}\right]

V_{n}=0.6 F_{y} A_{w}\left[C_{v 2}+\frac{1-C_{v 2}}{1.15\left[a / h+\sqrt{1+(a / h)^{2}}\right]}\right]

When $h / t_{w} \leq 1.10 \sqrt{k_{v} E / F_{y}}$

h / t_{w} \leq 1.10 \sqrt{k_{v} E / F_{y}}

(ii) When $1.10 \sqrt{k_{\mathrm{y}} E / F_{\mathrm{y}}} < h / t_{\mathrm{w}} \leq 1.37 \sqrt{k_{\mathrm{y}} E / F_{\mathrm{y}}}$

1.10 \sqrt{k_{\mathrm{y}} E / F_{\mathrm{y}}} < h / t_{\mathrm{w}} \leq 1.37 \sqrt{k_{\mathrm{y}} E / F_{\mathrm{y}}}

C_{v 2}=\frac{1.10 \sqrt{k_{\mathrm{y}} E / F_{\mathrm{y}}}}{h / t_{\mathrm{w}}}

(iii) When $h / t_{w}>1.37 \sqrt{k_{y} E / F_{y}}$

h / t_{w}>1.37 \sqrt{k_{y} E / F_{y}}

C_{v 2}=\frac{1.51 k_{y} E}{\left(h / t_{w}\right)^{2} F_{y}}