AISCAISC 360-22
Formulas

Formulas: Lateral-Torsional Buckling

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Formula 1

The maximum beam flexural strength, Mn=1.5MyM_{n}=1.5 M_{y}, will occur when the theoretical buckling moment, McrM_{c r}, reaches or exceeds 7.7My.My7.7 M_{y} . M_{y} is the moment at first yield in Equations F10-2 and F10-3, the same as the MyM_{y} in Equation F10-1.

Mn=1.5MyM_{n}=1.5 M_{y}

Formula 2

Mcr=2.33Eb4t(1+3cos2θ)(KL)2(sin2θ+0.156(1+3cos2θ)(KL)2t2b4+sinθ) (C-F10-1) M_{c r}=\frac{2.33 E b^{4} t}{\left(1+3 \cos ^{2} \theta\right)(K L)^{2}}\left(\sqrt{\sin ^{2} \theta+\frac{0.156\left(1+3 \cos ^{2} \theta\right)(K L)^{2} t^{2}}{b^{4}}+\sin \theta}\right) \quad \text { (C-F10-1) }

Formula 3

(the general expression for the critical moment of an equal-leg angle) with θ=45\theta=-45^{\circ} for the condition where the angle tip stress is compressive (see Figure C-F10.3).

θ=45\theta=-45^{\circ}

Formula 4

Using θ=45\theta=45^{\circ} in Equation C-F10-1, the resulting expression is Equation F10-5b with a +1 instead of -1 as the last term.

θ=45\theta=45^{\circ}

Formula 5

This is based on McrM_{c r} given in Equation C-F10-1 with θ=0\theta=0^{\circ}.

θ=0\theta=0^{\circ}

Formula 6

Lateral-torsional buckling will reduce the stress below 1.5My1.5 M_{y} only for Mcr<7.7MyM_{c r}<7.7 M_{y}.

Mcr<7.7MyM_{c r}<7.7 M_{y}

Formula 7

For an equal-leg angle bent about its major principal axis, this occurs for Lb/t3,700Cb/FyL_{b} / t \geq 3,700 C_{b} / F_{y}.

Lb/t3,700Cb/FyL_{b} / t \geq 3,700 C_{b} / F_{y}

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