AISCAISC 360-22
Formulas

Formulas: Block Shear Strength

PDF page 214 · AISC 360-22

Formula 1

The available strength for the limit state of block shear rupture along a shear failure path or paths and a perpendicular tension failure path shall be determined as follows:

Rn=0.60FuAnv+UbsFuAnt0.60FyAgv+UbsFuAntϕ=0.75 (LRFD) Ω=2.00 (ASD) \begin{aligned} R_{n} & =0.60 F_{u} A_{n v}+U_{b s} F_{u} A_{n t} \leq 0.60 F_{y} A_{g v}+U_{b s} F_{u} A_{n t} \\ \phi & =0.75 \text { (LRFD) } \\ \Omega & =2.00 \text { (ASD) } \end{aligned}

where

Ant= net area subjected to tension, in. 2( mm2)A_{n t}=\text { net area subjected to tension, in. }^{2}\left(\mathrm{~mm}^{2}\right)

Found in

On this page